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8x*2x^-2=x
We move all terms to the left:
8x*2x^-2-(x)=0
We add all the numbers together, and all the variables
-1x+8x*2x^-2=0
Wy multiply elements
16x^2-1x-2=0
a = 16; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·16·(-2)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{129}}{2*16}=\frac{1-\sqrt{129}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{129}}{2*16}=\frac{1+\sqrt{129}}{32} $
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